50n^2+140n+98=0

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Solution for 50n^2+140n+98=0 equation: 



50n^2+140n+98=0

a = 50; b = 140; c = +98;
Δ = b2-4ac
Δ = 1402-4·50·98
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$n=\frac{-b}{2a}=\frac{-140}{100}=-1+2/5$

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